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Medium o1-pro scores 26 on the Artificial Analysis Intelligence Index, below the median of 31 for similar models, indicating below-average intelligence despite strengths in reasoning tasks like math and science. Reasoning

o1-pro

o1-pro is OpenAI's most advanced reasoning model, leveraging extra compute power, reinforcement learning, and chain-of-thought processes to deliver consistently superior answers on complex challenges in math, science, coding, and beyond. Exclusively via the Responses API, it excels with a 200k context window and up to 100k output tokens for tackling your toughest problems.

200k Context
Medium o1-pro scores 26 on the Artificial Analysis Intelligence Index, below the median of 31 for similar models, indicating below-average intelligence despite strengths in reasoning tasks like math and science. Intelligence
Oct '23 Knowledge

Available for Chat, Vision, and File Uploads.

Performance Benchmarks

MMLU
91.8%
HumanEval
88.1%
MATH
96.4%

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Why use o1-pro?

Advanced Reasoning

Uses reinforcement learning and chain-of-thought to think through complex problems methodically before answering

Mathematical & Scientific Problem-Solving

Excels at mathematical computations, scientific reasoning, and advanced calculations requiring precise logical thinking

Complex Coding Analysis

Demonstrates remarkable ability to analyze large codebases, identify subtle bugs, and handle sophisticated programming challenges

Capability Examples

Complex Math Reasoning
Solve this integral: ∫(x^2 + sin(x)) dx from 0 to π, showing all steps.
The antiderivative is (1/3)x^3 - cos(x). Evaluating from 0 to π: [(1/3)π^3 - cos(π)] - [(1/3)(0)^3 - cos(0)] = (π^3/3 - (-1)) - (0 - 1) = π^3/3 +1 +1 = π^3/3 + 2. Exact value: approximately 10.335 + 2 = 12.335. Step-by-step derivation: integrate x^2 term by power rule, sin(x) by -cos(x).
Advanced Coding Challenge
Write a Python function to find the longest palindromic substring in "babad" using dynamic programming, with O(n^2) time.
def longest_palindrome(s): n = len(s); dp = [[False]n for _ in range(n)]; max_len, start = 1, 0; for i in range(n): dp[i][i] = True; for length in range(2, n+1): for i in range(n-length+1): j = i+length-1; if s[i]==s[j] and (length==2 or dp[i+1][j-1]): dp[i][j]=True; max_len=length; start=i; return s[start:start+max_len]. "bab" or "aba".

How to use

1
Go to Chat

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2
Select Model

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3
Type Prompt

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4
Interact

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